MathematicsChapter 35 min read

Calculus — The Definition and Applications of the Integral

O
OIYO ScienceContributor
3/4

The Antiderivative

The definition of an antiderivative:

  • If F’(x) = f(x), then F(x) is called an antiderivative of f(x)
  • Integral notation: ∫f(x)dx = F(x) + C (C: the constant of integration)

Basic integration formulas:

  • ∫x^n dx = x^(n+1)/(n+1) + C (n ≠ −1)
  • ∫(1/x) dx = ln|x| + C
  • ∫e^x dx = e^x + C
  • ∫a^x dx = a^x/ln(a) + C

Trigonometric integrals:

  • ∫sin(x) dx = −cos(x) + C
  • ∫cos(x) dx = sin(x) + C
  • ∫sec²(x) dx = tan(x) + C
  • ∫csc²(x) dx = −cot(x) + C

Linearity of integration:

  • ∫[f(x) ± g(x)]dx = ∫f(x)dx ± ∫g(x)dx
  • ∫k·f(x)dx = k·∫f(x)dx

Integration Technique 1: U-Substitution

U-substitution:

  • Let u = g(x), so du = g’(x)dx
  • Used for integrating complex composite functions

Procedure:

  1. Set u = g(x) (the inner function)
  2. Compute du = g’(x)dx
  3. Rewrite the expression in x in terms of u
  4. Integrate with respect to u
  5. Substitute back to x

Examples:

  • ∫2x·sin(x²)dx u = x², du = 2x dx = ∫sin(u)du = −cos(u) + C = −cos(x²) + C

  • ∫x/(1+x²) dx u = 1+x², du = 2x dx, x dx = du/2 = (1/2)∫(1/u)du = (1/2)ln|u| + C = (1/2)ln(1+x²) + C


Integration Technique 2: Integration by Parts

Integration by parts:

  • Formula: ∫u dv = uv − ∫v du
  • Used when integrating a product of two functions

The LIATE order (for choosing u):

  • L: Logarithmic
  • I: Inverse trigonometric
  • A: Algebraic (x^n)
  • T: Trigonometric
  • E: Exponential
  • Whichever comes earlier in the list is u, the rest is dv

Examples:

  • ∫x·e^x dx u = x, dv = e^x dx du = dx, v = e^x = xe^x − ∫e^x dx = xe^x − e^x + C

  • ∫ln(x) dx u = ln(x), dv = dx du = (1/x)dx, v = x = x·ln(x) − ∫x·(1/x)dx = x·ln(x) − x + C


The Definite Integral

The definition of the definite integral (a Riemann sum):

  • ∫[a to b] f(x)dx = lim(n→∞) Σf(x_i)·Δx
  • Intuitively: the (signed) area under the curve

Properties of the definite integral:

  • ∫[a to b] f(x)dx = −∫[b to a] f(x)dx
  • ∫[a to a] f(x)dx = 0
  • ∫[a to b] f(x)dx + ∫[b to c] f(x)dx = ∫[a to c] f(x)dx
  • ∫[a to b] [f+g]dx = ∫[a to b]f dx + ∫[a to b]g dx

Odd and even function properties (on the interval [−a, a]):

  • Even function f(−x) = f(x): ∫[−a to a] = 2∫[0 to a]
  • Odd function f(−x) = −f(x): ∫[−a to a] = 0

The Fundamental Theorem of Calculus

The Fundamental Theorem of Calculus, Part 1:

  • If F(x) = ∫[a to x] f(t)dt, then F’(x) = f(x)
  • Integration and differentiation are inverse operations

The Fundamental Theorem of Calculus, Part 2:

  • ∫[a to b] f(x)dx = F(b) − F(a)
  • Use any F(x) with F’(x) = f(x) to compute the definite integral

Worked examples:

  • ∫[0 to π] sin(x)dx = [−cos(x)]₀^π = −cos(π) − (−cos(0)) = 1 + 1 = 2

  • ∫[1 to e] (1/x)dx = [ln|x|]₁^e = ln(e) − ln(1) = 1 − 0 = 1

The mean value theorem for integrals:

  • There exists a c in [a,b] such that ∫[a to b] f(x)dx = f(c)(b−a)
  • f(c) is the average value of the integral

Applications of Integration

Area:

  • Area above the x-axis: A = ∫[a to b] f(x)dx (f(x) ≥ 0)
  • Area between two curves: A = ∫[a to b] [f(x)−g(x)]dx (f≥g)

Example: the area between y=x² and y=x

  • Intersection points: x²=x → x=0, x=1
  • A = ∫[0 to 1] (x−x²)dx = [x²/2 − x³/3]₀¹ = 1/2 − 1/3 = 1/6

Volume of a solid of revolution:

  • Rotation about the x-axis: V = π·∫[a to b] [f(x)]²dx (the disk method)
  • Rotation about the y-axis: V = 2π·∫[a to b] x·f(x)dx (the shell method)

Arc length:

  • L = ∫[a to b] √(1 + [f’(x)]²) dx

Average value:

  • The average of a function: f_avg = (1/(b−a)) ∫[a to b] f(x)dx

Frequently Asked Questions

Q. When should I use substitution versus integration by parts? A. Substitution works well when a composite function f(g(x)) appears alongside its derivative g’(x) — in other words, an integral of the form ∫f(g(x))·g’(x)dx. Integration by parts is used when two different types of functions are multiplied together — algebraic × trigonometric as in ∫x·sin(x)dx, algebraic × exponential as in ∫x·e^x dx, or a logarithm as in ∫ln(x)dx.

Q. Can a definite integral come out negative? A. Yes, it can. A definite integral is negative when the function lies below the x-axis. For example, ∫[π to 2π] sin(x)dx = −2. To find the actual “area,” you’d need to integrate |f(x)| or split the region above and below the x-axis. Remember that a definite integral is a “signed area” — it’s a directional quantity.

O

OIYO Science

Science Desk

The OIYO science desk explains astronomy, physics, and everyday science with structure before memorization. We translate textbook concepts and current consensus into plain analogies, checked so simplification never distorts the facts.